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qxysocket1
- Windows Sockets规范本意在于提供给应用程序开发者一套简单的API，并让各家网络软件供应商共同遵守。-Windows Sockets norms are meant to provide application developers a simple A PI, and allow various network software vendors mutual respect.
qxysocket
- Windows Sockets规范本意在于提供给应用程序开发者一套简单的API，并让各家网络软件供应商共同遵守。-Windows Sockets norms are meant to provide application developers a simple A PI, and allow various network software vendors mutual respect.
BSDSocket
- Windows Sockets规范本意在于提供给应用程序开发者一套简单的API，并让各家网络软件供应商共同遵守。-Windows Sockets norms are meant to provide application developers a simple A PI, and allow various network software vendors mutual respect.
zhuanjia111
- 用专家系统优化下面的PID参数或设计一个专家控制器，被控对象为 并与PI控制算法进项比较-use expert system optimization below the PID parameters, or a design expert controller, and object to the PI control algorithm with a credit comparison
epm7032ae
- (1) This pin may function as either a JTAG port or a user I/O pin. If the device is configured to use the JTAG ports for in-system programming, this pin is not available as a user I/O pin. (2) The user I/O pin count includes dedicated input pins
piclassic
- 计算pi ** Pascal Sebah : September 1999 ** ** Subject: ** ** A very easy program to compute Pi with many digits. ** No optimisations, no tricks, just a basic program to learn how ** to compute in multiprecision.
进程管理模拟
- 系统资源(r1…rm),共有m类，每类数目为r1…rm。随机产生进程Pi(id,s(j,k)，t),0<=i<=n,0<=j<=m,0<=k<=dt为总运行时间，在运行过程中，会随即申请新的资源。描述进程运行状态。-system resources (r1 ... rm), a total of m category, the number of each type of r1 ... rm. The process of randomly generated
cup
- 第四节百度杯A题答案。水杯的问题！To solve this problem, you should know that the volume of one cup is pi * (r * r + R * R + r * R) * h / 3. If you don t know this formula, you could find by this formula: s * h / 3. It s the formula to calculte the volume of ta
circle
- function [] = circleagain(a,b,c,r) pixel = 0.1 theta1 = 0 theta2 = 360*pi/180 pix = pixel/r theta = theta1:pix:theta2 global x y z x = a + r*cos(theta) y = b + r*sin(theta) z = ones(1,length(x))*c x=round(x*10)/10 y=ro
Dialog
- 老师上课讲的一个计算圆周率的例子，是基于QT的简单对话框的实现。-A calculation of pi example the teacher talked about, is to achieve a simple dialog based on QT
11
- empirical formula with kaiser clc clear all fs=1000 fc=250 df=50 r=0.001 f=fc/fs dw=2*pi*(df/fs) a=-20*log(r) n=floor(((a-8)/(2.285*dw))+1) if a>50 b=0.1102*(a-8.7) elseif a>=21 && a<=50 b=0.5842*((a-
EEE-212-lab-sheet
- empirical formula with kaiser clc clear all fs=1000 fc=250 df=50 r=0.001 f=fc/fs dw=2*pi*(df/fs) a=-20*log(r) n=floor(((a-8)/(2.285*dw))+1) if a>50 b=0.1102*(a-8.7) elseif a>=21 && a<=50 b=0.5842*((a-