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acm
- 北大OJ,3668到3673题源码,全部是通过代码-3070:The cows are so very silly about their dinner partners. They have organized themselves into three groups (conveniently numbered 1, 2, and 3) that insist upon dining together. The trouble starts when they line up at the
FOJ_1683
- FOJ的1683题,采用二分矩阵乘法的实现,源代码已在OJ上测试通过-FOJ' s 1683 title, with the realization of the binary matrix multiplication, the source code has been tested in the OJ by
HDU-2653--BFSPpriority_queue
- 这是算法题目代码,题目为杭州电子科技大学oj平台的2653题(HDU 2653),此题目用到了记忆化搜索和优先队列的算法,读题较为麻烦-This is the algorithm topic code, entitled Hangzhou University of Electronic Science and Technology 2653 oj platform title (HDU 2653), this topic uses the memory of search and priori
new-oj
- 为大家分享一下RMQ算法,非常好用的士兵杀敌程序-RMQ algorithm to share with you, very nice program soldier kills
choose7
- 华为oj 训练场中中级题,编程环境visual studio2010,控制台应用程序-Huawei oj in intermediate title field, visual studio2010 programming environment, the console application
IsLegalIp
- 华为oj训练场基础题,判断是否是合法IP地址-Huawei oj training base, determine whether legitimate IP addresses
max_pulic_substring_lenth
- 华为oj训练场题目,判断两个字符串的最大公共子串的长度-Huawei oj training topic, whether two strings of the length of the largest public substring
hechangdui
- 华为oj基础训练题,合唱队,共N个人挑出N-K个人,剩下的组成中间高两边递减的合唱队-Huawei oj basic training topic, chorus, a total of N pick N- K individuals, diminishing the rest of the middle high on both sides of the chorus
last_word_lenth
- 华为oj训练场初级题目,输出字符串最后一个单词长度-Huawei oj training primary title, last word length output string
huaweiOJ_key
- 华为OJ c++答案,华为机试刷题库专用,考前必备-华为OJ c-huaweiOJ c++ answer,prepare for huawei
pkpdx
- 华为OJ平台题目 纸牌满分代码-Huawei OJ platform CARDS out of the code